PHP 如何获取jsonp传的数组
本帖最后由 zl2727 于 2014-01-09 14:19:55 编辑
1 | var urlstr = "{GID:'" + $( "#hogid" ).val() + "',Name:'" + $( "#txtName" ).val() + "',ProvinceID:'" + $( "#ProvinceID" ).val() + "',CityID:'" + $( "#CityID" ).val() + "',AreaID:'" + $( "#AreaID" ).val() + "',Moblie:'" + $( "#txtMobile" ).val() + "',Address:'" + $( "#txtAddress" ).val() + "',PayType:'" + itemvalue + "'}" ;<br /> $.ajax({<br /> url: "http://www.xxx.com/car.php" ,<br /> type: "POST" ,<br /> data: urlstr,<br /> async:false,<br /> dataType: 'jsonp' ,<br /> jsonp: "callback" ,<br /> jsonpCallback: "getgoods" , <br /> success: function (data) {<br /> alert(data.res);<br /> },<br /> error: function (err) {<br /> alert( "网络加载繁忙,请刷新!" );<br /> }<br /> });
|
Copy after login
如何获取到 data
我的PHP文件中
1 | $urlstr = $_POST ;<br /> echo $urlstr .Name;<br />
|
Copy after login
什么都没有 应该如何编写?