AJAX PHP 循环之后点击状态更换图片,该如何解决
AJAX PHP 循环之后点击状态更换图片
foreach ( $account as $key => $value)
{
?>
');">
}
else{
?>
');">
function xingxing(id,name){
$.ajax({
type: "POST",
url: "",
processData: "false",
data: "n=" + Math.random() + "&fn=" + escape(id) + "&starflag=" + escape(name) + "",
success: function(msg){
var msg = $.trim(msg);
switch (msg){
case "200":
location.replace(location.href);
case "110": //重新登录
location.replace(location.href);
case "120": //修改密码
location.replace(location.href);
break;
default:
alert("失败");
location.replace(location.href);
break;
}
}
});
}
------------------------------------------------------------------------------
我的问题是 调用AJAX 之后直接更换图片不需要在从新刷新一次页面,求大虾帮忙,在线等
------解决方案--------------------
不知道你要做什么?
既然是用了 jquery,那么就该用 jquery 的传统写法
php 部分
<span class="img"><br /><img src="/static/imghw/default1.png" data-src="/themes/default/images/star02.gif" class="lazy" style="max-width:90%"starflag'] == 1? '' : 'none' ? alt="AJAX PHP 循环之后点击状态更换图片,该如何解决" >" name="<?php echo $value['name']?>" id="<?php echo $value['id']?>" /> <br /><img src="/static/imghw/default1.png" data-src="/themes/default/images/star01.gif" class="lazy" style="max-width:90%"starflag'] == 1? 'none' : '' ? alt="AJAX PHP 循环之后点击状态更换图片,该如何解决" >" name="<?php echo $value['name']?>" id="<?php echo $value['id']?>" /> <br /></span><br />
js 部分
$(function() {<br> $(".img").click(function() {<br> $(this).children().toggle();<br> $.post("<?php echo base_url('test/fangfa'); ?>",<br> {<br> n : Math.random(),<br> fn : escape($(this).attr('id')),<br> starflag : escape($(this).attr('name'))<br> },<br> function(msg){<br> //你需要的其他处理<br> });<br> });<div class="clear"> </div>

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