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ajax技术 始终出去发送状态,该如何解决

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Release: 2016-06-13 11:49:24
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ajax技术 始终出去发送状态
ajax.js代码:
       var xmlHttp;
function S_xmlhttprequest(){
    if(window.ActiveXObject){
       xmlHttp=new ActiveXObject("Microsoft.XMLHTTP");
    }
    else if(widow.XMLHttpRequest){
       xmlHttp=new XMLHttpRequest();
    }
}
function funphp100(url){
    S_xmlhttprequest();
    xmlHttp.open("GET","for.php?id="+url,true);
    xmlHttp.onreadystatechange=byphp;
    xmlHttp.send(null);
}
function byphp(){
   if(xmlHttp.readyState==1){
   document.getElementById('php100').innerHTML="loading....";
   }
   if(xmlHttp.readyState==4){

          var byphp100 = xmlHttp.responseText;
          document.getElementById('php100').innerHTML=byphp100;

    }

}
for.php代码
          if($id=$_GET[id]){
  for($i=1;$i
echo $i;
sleep(2);
   }
   exit();
}
?>
index.php代码:
          <script></script>
o
t
x



------解决方案--------------------
if($id=$_GET[id]){<br />  for($i=1;$i<=5;$i++){<br /><br />echo $i;<br />//sleep(2);<br />   }<br />   exit();<br />}
Copy after login

<html><br /><head><br />	<title> </title>	<br />	<script type="text/javascript" src='jquery-1.4.2.min.js'></script><br /><br /></head><br /><script type="text/javascript"><br />	var xmlHttp;<br />	function S_xmlhttprequest(){<br />		if(window.ActiveXObject){<br />			xmlHttp=new ActiveXObject("Microsoft.XMLHTTP");<br />		}<br />		else if(window.XMLHttpRequest){<br />			xmlHttp=new XMLHttpRequest();<br />		}<br />	}<br />	function funphp100(url){<br />		S_xmlhttprequest();<br />		xmlHttp.open("GET","test.php?id="+url,true);<br />		xmlHttp.onreadystatechange=byphp;<br />		xmlHttp.send(null);<br />	}<br />	function byphp(){<br />		if(xmlHttp.readyState==1){<br />			document.getElementById('php100').innerHTML="loading....";<br />		}<br />		if(xmlHttp.readyState==4){<br /><br />			var byphp100 = xmlHttp.responseText;<br />			document.getElementById('php100').innerHTML=byphp100;<br /><br />		}<br /><br />	}<br /><br /></script><br /><body><br />	<a href= "#" onclick="funphp100('o')">o</a><br />	<a href= "#" onclick="funphp100('t')">t</a><br />	<a href= "#" onclick="funphp100('x')">x</a><br />	<br><br />	<div id="php100"></div><br /></body><br /></html>
Copy after login


------解决方案--------------------
else if(widow.XMLHttpRequest){
       xmlHttp=new XMLHttpRequest();
    }
window
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source:php.cn
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