php写WebService无法通信,该怎么解决

WBOY
Release: 2016-06-13 11:50:34
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php写WebService无法通信
客户端代码:

<br /><?php<br />    $client = new SoapClient(null, array('location'=>"http://192.168.1.100/test/serverSoap.php",'uri' =>"http://soap/"));<br />    echo $client->show();  <br />?><br />
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服务器代码:
<br /><?php<br />    class test{<br />        function show(){<br />            return 'the data you request';<br />        }<br />    }<br />    function getUserInfo($name){<br />        return 'fbbin';<br />    }<br />    $soap = new SoapServer(null, array('uri'=>'http://soap/','location'=>'http://localhost/test/serverSoap.php'));<br />    $server->serClass('test');<br />    $server->handle();<br />?><br />
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运行环境用的wamp,以上两个文件都放在wamp安装目录的www/test/目录下。

操作系统window 8

打开浏览器,访问客户端文件

http://localhost/test/serverClient.php

显示错误信息如下:

我是新手啊,php刚学没几天,webservice也只是知道用来干啥的,从来没用过。麻烦诸位讲的通俗一点可不可以啊,谢谢回答。

php的soap服务以打开。
php的soap服务以开启:

------解决方案--------------------
太粗心了,这样写
<?php<br />    class test{<br />        function show(){<br />            return 'the data you request';<br />        }<br />    }<br />    function getUserInfo($name){<br />        return 'fbbin';<br />    }<br />    $server = new SoapServer(null, array('uri'=>'http://soap/','location'=>'http://localhost/test/serverSoap.php'));<br />    $server->setClass('test');<br />    $server->handle();<br />?>
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------解决方案--------------------
补充下

<br /><?php<br />    class test{<br />        function show(){<br />            return 'the data you request';<br />        }<br /><br />        function getUserInfo($name){<br />            return 'fbbin';<br />        }<br />    }<br />    $server = new SoapServer(null, array('uri'=>'http://soap/','location'=>'http://localhost/test/serverSoap.php'));<br />    $server->setClass('test');<br />    $server->handle();<br />?><br />
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