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json对象的变换,新手求大神帮忙

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Release: 2016-06-13 11:51:26
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json对象的转换,新手求大神帮忙
json格式如下
   {"loginResult":{"code":"005","teamId":"1","password":"123","role":"员工","roleId":"2"}}

我用的CI框架 在models  里面定义了一个Member_Model对象,属性有code,teamId,password,role,roleId
怎样将上面的JSON数据转换成对象赋给Member_Model


------解决方案--------------------

$json = '{"loginResult":{"code":"005","teamId":"1","password":"123","role":"员工","roleId":"2"}}';<br />$arr = json_decode($json);<br />$mm = new Member_Model();<br />foreach ($arr->loginResult as $key => $value) {<br />	$mm->$key = $value;<br />}
Copy after login

------解决方案--------------------
$s='{"loginResult":{"code":"005","teamId":"1","password":"123","role":"员工","roleId":"2"}}';<br />$o = json_decode($s);<br />print_r($o->loginResult);
Copy after login

------解决方案--------------------
如果是
$result = json_decode($buffer, true);

$member = $result['loginResult'];

如果是
$result = json_decode($buffer);

$member = $result->loginResult;

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