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PHP 获取二维数组中某个key的聚合

Jun 13, 2016 am 11:53 AM
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PHP 获取二维数组中某个key的集合

本文为代码分享,也是在工作中看到一些“大牛”的代码,做做分享。

具体是这样的,如下一个二维数组,是从库中读取出来的。

代码清单:

$user = array(    0 => array(        'id'    => 1,        'name'  => '张三',        'email' => [email protected]',    ),    1 => array(        'id'    => 2,        'name'  => '李四',        'email' => [email protected]',    ),    2 => array(        'id'    => 5,        'name'  => '王五',        'email' => [email protected]',    ),    ......);
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上面的数组格式,主要大家玩过 PHP+MYSQL,就肯定非常熟悉了。

那么,现在有这样的两个需求:

1)获取索引"id"的集合,并且保存为一个一位数组,即得到 array(1,2,5)

不知道各位朋友会怎么写呢?

如果是以前我的写法就是直接 foreach,然后 array_push 一个个的往一个数组变量里塞。这样也能实现。但这样的写法很影响性能,因为使用 PHP 原生的函数肯定比循环效率高。

代码清单:

$ids = array();$ids = array_map('array_shift', $user);
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如上代码就可以得到我们想要的结果了,关于函数的使用想看手册。

其实这里面还有一种方案,使用 array_column 函数,不过此函数需要 PHP 版本要求,(PHP 5 >= 5.5.0)

代码清单:

$ids = array();$ids = array_column($user, 'id');
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这样的话,效率肯定会更高了。


2)获取索引"name"的集合,并且保存为一个一位数组,即得到 array('张三','李四',‘王五’)

按照,我以往的写法,还是一样的foreach,然后 array_push 一个个的往一个数组变量里塞。请看高效率的代码清单。

代码清单:

$names = array();$names = array_reduce($user, create_function('$v,$w', '$v[$w["id"]]=$w["name"];return $v;'));
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得到结果:

array(    1 => '张三',    2 => '李四',    5 => '王五',);
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经常 foreach 的童鞋,赶快更正吧!

本文来自CSDN,转载请注明出处!http://blog.csdn.net/liruxing1715/article/details/22925575

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