MYSQL中截取数据库时间字段等于提交上来的值如何写MYSQL语句

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Release: 2016-06-13 11:56:53
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MYSQL中截取数据库时间字段等于提交上来的值怎么写MYSQL语句
bl_time是字段(如2014-05-09 11:33:20)
$Year是表单提交上来的值(如2014)

.....where YEAR('ruku.bl_time')=" . $Year;

意思就是截取bl_time字段的年份等于表单提交上来的$Year的值
where 后面的语句怎么写才正确?
------解决方案--------------------

<br /><br />$sql = "select * from table where year(bl_time) = '$Year'";<br /><br />
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------解决方案--------------------
用month() 和 day() 是没问题的,你试了吗。

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