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懂PHP且懂点C的大神进去

Jun 13, 2016 pm 12:03 PM
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懂PHP且懂点C的大神进来
这是个客户端C版本的解密函数,我需要一个PHP版本的加密函数,麻烦下大神,

<br />void hdth_normal_decode(char * outstr,char * instr)<br />{<br />	int   i=0;<br />	int j = 0;<br />	int len = strlen(instr);<br />	for(i=0;i<len;i=i+2)   <br />	{   <br />		int   h=(instr[i]-'c');   <br />		int   l=(instr[i+1]-'f');   <br />		char  c=(l<<4)+(h&0xf);   <br />		outstr[j]=c;<br />		j++;<br />	}   <br /><br />	return;<br />}<br />
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给个原文转为密文的例子:

<br />原文:www.comunits.net<br />密文:jmjmjmqhflrlplhmqlllgmfmqhqlhlgm<br />
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------解决方案--------------------
先移植解密函数到 php
function hdth_normal_decode($in) {<br />  $out = ''; <br />  $len = strlen($in);<br />  for($i=0; $i<$len; $i+=2) {<br />    $h = ord($in{$i}) - ord('c');<br />    $l = ord($in{$i+1}) - ord('f');<br />    $c = ($l << 4) + ($h & 0xf);<br />    $out .= chr($c);<br />  }<br />  return $out;<br />}
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然后求其逆运算
function hdth_normal_encode($in) {<br />  $out = '';<br />  $len = strlen($in);<br />  for($i=0; $i<$len; $i++) {<br />    $c = ord($in{$i});<br />    $l = ($c >> 4) + ord('f');<br />    $h = ($c & 0xf) + ord('c');<br />    $out .= chr($h) . chr($l);<br />  }<br />  return $out;<br />}
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测试一下
echo hdth_normal_encode('www.comunits.net');
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jmjmjmqhflrlplhmqlllgmfmqhqlhlgm

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