php 循环异常

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Release: 2016-06-13 12:06:00
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php 循环错误


 include_once 'mysql.php';
 
 $C = "";
 $rownum = 5;          //每行要显示的车标数
 $picindex = 1;          //$picindex 车标序号
 $newrow = 0;            //是否换行 ,值为 1 时换行(换行即为要输入 ,为 0 时不换行
 $logorst = mysqli_query($cnn,"select * from BandLogo where ShowOrder  '0' ORDER BY ShowOrder ASC");
 
 ?> while($row = mysqli_fetch_array($logorst)){
      if($picindex > $rownum){
         $picindex = 1;
         $newrow = 1;
      }         
      if($newrow == 1){         
         echo "";                  //输出  即为 换行         
      } ?>    
            if($newrow == 1){
         echo "";
         $newrow = 0;
      }    
      $picindex++;                  
}
 ?>
     
        
              
           
           ">
php 循环异常 "/>

        

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上面的代码想要每行显示5个图标,但是从第二行开始,就会在第一个图片显示了之后换行,请帮我看看那里有错误呢,谢谢了
------解决方案--------------------
你的
      if($newrow == 1){         
         echo " ";                  //输出   即为 换行         
      }
     if($newrow == 1){
         echo "";
         $newrow = 0;
      }    
是在一次循环中完成的,自然那行就只有一个单元格了
------解决方案--------------------
标签不完整
if($picindex > $rownum){
         $picindex = 1;
         $newrow = 1;
      }   

前五次$picindex 肯定小于$rownum ,也就是说刚开始并没有的开始标签
------解决方案--------------------
循环里面改为
      if($picindex > $rownum){<br>         $picindex = 1;<br>      }         <br>      if($picindex == 1){         <br>         echo "<tr>";                  //输出 </tr><tr> 即为 换行         <br>      } ?>    <br>      <td>     <br>        <table><tr><td>              <?php  //定义一个小的表格,只有两个格子,上面一个格子放图片,下面一个格子放名称  ?><div class="clear">
                 
              
              
        
            </div>
</td></tr></table>
</td>
</tr>
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