PHP Undefined index报错的修复方法
虽然可以通过设置错误显示方式来隐藏这个提示,但是这样也有隐患,就是在服务器的日志中会记录这些提示,导致日志文件异常庞大。
首先,这个不是错误,是warning。所以如果服务器不能改,每个变量使用前应当先定义。网上流行的解决方法有以下几种:
方法1:服务器配置修改。修改php.ini配置文件,error_reporting = E_ALL & ~E_NOTICE。
方法2:对变量进行初始化,规范书写(比较烦琐,因为有大量的变量)。但还没有找到好定义方法,望大家指教。
方法3:每个文件头部加上:error_reporting(0); 如果不行,只有打开php.ini,找到display_errors,设置为display_errors = Off。以后任何错误都不会提示。
方法4 :做判断:isset($_GET["page"]) if-else判断。或者加上'@'表示这行如果有错误或是警告不要输出。如:@$page=$_GET["page"]
方法5:file1.php文件把$xx变量付一个值,用post 传递给file2.php,如果file2.php没有$xx的定义,而直接使用$yy=$xx; 系统就会报错:"undifined variaable $xx", 如果file2.php的文件开始用$xx="";定义,那么file1.php的$xx值就传不过来了。file2.php里可以这样:if(!isset($xx)) $xx="";
如果你觉得上面的方法不怎么好用,也可以用下面的方法:
复制代码 代码如下:
function _get($str){
$val = !empty($_GET['str']) ? $_GET['str'] : null;
return $val;
}
定义这样的一个函数,然后在用的时候,直接用 _get('str') 代替 $_GET['str'] 就行啦~这样会方便些。

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