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php中用三元函数判断数字的奇偶性的异常,请教如何解决

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Release: 2016-06-13 12:07:08
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php中用三元函数判断数字的奇偶性的错误,请问怎么解决
Parse error: syntax error, unexpected 'echo' (T_ECHO) in F:\xampp\htdocs\test\test02.php on line 26 这是错误描述,

下面是源代码:
   for($a =0;$a  //用三元运算输出,如果没有余数则是偶数,
        否则为奇数      
    echo $a %2==0?$a."是偶数"."\n":$a."是奇数"."\n"; 
 }  
?> 
------解决思路----------------------
//否则为奇数
------解决思路----------------------
for($a =0;$a  //用三元运算输出,如果没有余数则是偶数,否则为奇数      
  echo $a %2==0?$a."是偶数"."\n":$a."是奇数"."\n"; 
}

------解决思路----------------------

<br /> for($a =0;$a<10;$a++){    <br />  //用三元运算输出,如果没有余数则是偶数,<br />        //否则为奇数      <br />    echo $a%2==0?$a."是偶数"."\n":$a."是奇数"."\n"; <br /> }  <br /><br />
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<br />0是偶数 1是奇数 2是偶数 3是奇数 4是偶数 5是奇数 6是偶数 7是奇数 8是偶数 9是奇数 <br /><br />
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