表单$_post[]的有关问题
表单$_post[]的问题
表单action指向本身所在页面
提交按钮
下面有一个判断 if($_Get['search'])
如果有值,说明点击了查询按钮,执行啥啥操作
如果没有值,仅仅显示本页面静态部分。
5.3可以运行
使用PHP5.5之后却无法显示该网页
请问解决办法吧。这是怎么回事?所有代码都需要重写?
------解决思路----------------------
$_GET[search]
不加引号。PHP首先会查找search常量,找不到所以就报错了。
如果不想改代码,可以在首行加上:error_reporting(E_ALL & ~E_NOTICE); 这句,就可以将notice错误报告屏蔽掉。
------解决思路----------------------
你可以把错误调试打开,如果是网页无法显示,应该是哪里有问题。
------解决思路----------------------
加引號這個是標準寫法。
為什麼不按標準呢。。
------解决思路----------------------
出现这个错误提示的原因,PHP会把没有引号引起来的键名当作是常量去获取, 当找不到的时候, 抛出一个NOTICE, 然后再根据“常量名”生成一个字符串, 然后再讲这个字符串做为键名继续~
可以設置error_reporting(E_ALL & ~E_NOTICE); 來屏蔽錯誤顯示。但最好還是加引號,這樣不需要在將常量轉字符去獲取多次,提高效率。
------解决思路----------------------
这与 php 版本无关,但与 php 环境设置有关
当然,随着 php 版本的升级,你受到的约束也在升级
if($_Get['search']) 将可能会产生一个 E_NOTICE 级别的错误信息
如果你没有打开错误显示,或将错误信息重定向到日志
那么由于错误信息没有出路,导致一个 HTTP 500 状态(服务器拒绝响应)
虽然屏蔽掉 E_NOTICE 级别错误检查,可以回避掉这个毛病
但隐患终究是存在的,程序是不健壮的

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