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The difference between quick sorting php and javascript_javascript skills

WBOY
Release: 2016-05-16 18:10:29
Original
1557 people have browsed it
1. PHP
复制代码 代码如下:

$unsorted = array(2,4,5,63,4,5,63,2,4,43);
function quicksort($array)
{
if (count($array) == 0)
return array();
$pivot = $array[0];
$left = $right = array();
for ($i = 1; $i < count($array); $i ) {
if ($array[$i] < $pivot)
$left[] = $array[$i];
else
$right[] = $array[$i];
}
return array_merge(quicksort($left), array($pivot), quicksort($right));
}
$sorted = quicksort($unsorted);
print_r($sorted);

2. JavaScript
复制代码 代码如下:

var a = [2,4,5,63,4,5,63,2,4,43];
function quicksort(arr)
{
if (arr.length == 0)
return [];
var left = new Array();
var right = new Array();
var pivot = arr[0];
for (var i = 1; i < arr.length; i ) {
if (arr[i] < pivot) {
left.push(arr[i]);
} else {
right.push(arr[i]);
}
}
return quicksort(left).concat(pivot, quicksort(right));
}
console.log(quicksort(a));

注意,第一个条件语句是很重要的!而在PHP中COUNT函数将返回一个NULL值或空数组或0代替,你可以像count($array)<2的东西它
复制代码 代码如下:

if (count($array) < 2)
return $array;

在JavaScript中你无法使用,由于对'未定义'的值时,存在一个“空“数组作为参数传递。因此,需要包含上面的条件:
复制代码 代码如下:

// this will result with an error
if (arr.length < 2)
return arr;
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source:php.cn
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