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PHP 作用域解析运算符(::)

Jun 13, 2016 pm 12:14 PM
joomla php Scope Source code of look parse operator

Scope Resolution Operator (::)
今天 看joomla源码的时候,才意识到。原来这个操作符还可以访问类的非静态方法啊。真的让我吃惊不好。一直以为作用域解析运算符只能访问类的static方法和static成员变量。
如果各位不相信,下面有个简单的小测试代码可以证明这个。

复制代码 代码如下:


class A{
private $_name = 'A';
function __construct(){
echo 'A construct
';
}
function test(){
echo 'A test()
';
}
}
class B extends A{
private $_name = 'B';
function __construct(){
parent::__construct();
echo 'B construct
';
}
function test(){
echo 'B test()';
}
}
A::test();
echo '#########
';
B::test();


这段代码输入的结果为:

复制代码 代码如下:


A test()
#########
B test()


虽然A类中的test()和B类中的test都不是 static方法,但是一样可以用 “类名::方法名称(参数列表)” 的样式进行正确调用。他的效果和 new 一个类的实例,然后用这个实例调用
test方法是一个样的。
但是,如果我需要在test方法中打印name属性,直接用::来调用 会是怎么个情况那.我们首先来修改下 上面的代码。

复制代码 代码如下:


class A{
private $_name = 'A';
function __construct(){
echo 'A construct
';
}
function test(){
echo 'A test()
', $this->$_name,'
';
}
}
class B extends A{
private $_name = 'B';
function __construct(){
parent::__construct();
echo 'B construct
';
}
function test(){
echo 'B test()', $this->_name,'
';
}
}
A::test();
echo '#########
';
B::test();


上面的代码运行的结果 如下:

复制代码 代码如下:


Fatal error: Using $this when not in object context in D:\www\test\scoperefe.php on line 9
[html]
那有的朋友就说了。你压根就没有实例化类A,当然不能直接用$this->_name的方式来访问成员变量$_name了,那么,是不是修改成self::$_name就行了哪?
说干就干,下面把上面的代码修改下
[code]
class A{
private $_name = 'A';
function __construct(){
echo 'A construct
';
}
function test(){
echo 'A test()
', self::$_name,'
';
}
}
class B extends A{
private $_name = 'B';
function __construct(){
parent::__construct();
echo 'B construct
';
}
function test(){
echo 'B test()', $this->_name,'
';
}
}
A::test();
echo '#########
';
B::test();


再运行上面的代码,结果如下:

复制代码 代码如下:


A test() Fatal error: Access to undeclared static property: A::$_name in D:\www\test\scoperefe.php on line 9



哦,原来不能用self 关键字访问当前类的非static方法。
现在,如果想正确的调用这个方法,有2个做法:
1、首先实例化类,然后用对象调用就可以直接使用$this->_name进行调用了;
2、将成员变量$_name设置为static;

上面的问题,相信大家都能够正确的处理。

其实我真正想说的是:
如果一个方法可以不进行实例化就调用,那么我们最好把这个方法使用static关键字修饰下。在实现方法的时候,只调用该类的static成员变量。这样就不会出现上面遇到问题了。
如果一个方法没有设置为static的方法。那么,最安全的做法还是用实例对象进行调用更为安全,因为,说不定什么时候就需要修改该方法的实现,在修改的时候,说不定就要调用该类中的
非static成员变量(因为,很大程度上在修改方法的实现的时候,已经忘记还有用类名直接调用这么一说)。

个人愚见。
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