怎么做数据库的行列转置?

WBOY
Release: 2016-06-13 12:15:59
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如何做数据库的行列转置??
thinkphp和mysql。数据库如图所示:

建表的sql语句如下:

<br />CREATE TABLE `score_collect` (<br />   `std_id` int(10) NOT NULL,<br />   `course_id` int(11) NOT NULL,<br />   `score` varchar(255) DEFAULT NULL,<br />   PRIMARY KEY (`std_id`,`course_id`),<br /> )<br />
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<br />INSERT INTO `score_collect` VALUES ('2012508082', '2', '20');<br /> INSERT INTO `score_collect` VALUES ('2012508082', '3', '10');<br /> INSERT INTO `score_collect` VALUES ('2012508082', '4', '30');<br /> INSERT INTO `score_collect` VALUES ('2012508084', '2', '21');<br /> INSERT INTO `score_collect` VALUES ('2012508084', '3', '11');<br /> INSERT INTO `score_collect` VALUES ('2012508084', '4', '31');<br />
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需要实现的是将上图中的数据调整为这样在前台显示出来:

其中,表行数不固定。std_id和course_id也不固定。
(不知道我把问题表达清楚了没有)。用php也可以,但是我想最好还是用sql语句吧。当然。。能兼顾性能最好。
跪求各路大神解决,谢谢。
另外祝大家春节快乐,万事如意。 谢谢
------解决思路----------------------
<br />SELECT std_id,GROUP_CONCAT(course_id) AS course_id,GROUP_CONCAT(score) AS score FROM `score_collect` GROUP BY std_id;<br />
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<br />//$list=array(array('std_id'=>'2012508082','course_id'=>'2,3,4','score'=>'20,10,30'),array('std_id'=>'2012508084','course_id'=>'2,3,4','score'=>'21,11,31'),);<br /><br />foreach($list as $key=>$val)<br />{<br />	$course_id_arr=explode(',',$val['course_id']);<br />	$score_arr=explode(',',$val['score']);<br />	unset($list[$key]['course_id']);<br />	unset($list[$key]['score']);<br />	foreach($course_id_arr as $key1=>$val1)<br />	{<br />		$list[$key][$val1]=$score_arr[$key1];<br />	}<br />}<br /><br />print_r($list);<br />
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