socket通信 php作为客户端,C++作为服务端通信有关问题。

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Release: 2016-06-13 12:16:01
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socket通信 php作为客户端,C++作为服务端通信问题。。。
最近想做一个如题这样的东西,现在php发送能成功,C++做出正确的相应:发送一段json字符串,但是C++发出的消息php怎么也收不到。。。不知道这是为什么。。请大家帮帮忙   难道是C++传给php的消息格式有什么问题?重点问题我感觉出在socket_read上。。但是没搞明白

<?php<br />error_reporting(E_ALL);<br />set_time_limit(0);<br />echo "<h2>TCP/IP Connection</h2>\n";<br /><br />$port = 6000;<br />$ip = "127.0.0.1";<br /><br /><br />$socket = socket_create(AF_INET, SOCK_STREAM, SOL_TCP);<br />if ($socket < 0) {<br />    echo "socket_create() failed: reason: " . socket_strerror($socket) . "\n";<br />}else {<br />    echo "OK.\n";<br />}<br /><br />echo "试图连接 '$ip' 端口 '$port'...\n";<br />$result = socket_connect($socket, $ip, $port);<br />if ($result < 0) {<br />    echo "socket_connect() failed.\nReason: ($result) " . socket_strerror($result) . "\n";<br />}else {<br />    echo "连接OK\n";<br />}<br /><br />$in = 'r';<br />$out ='';<br /><br />	if(!socket_write($socket,$in,strlen($in))) {<br />		echo "socket_write() failed: reason: " . socket_strerror($socket) . "\n";<br />	}else {<br />		<br />		echo "发送到服务器信息成功!\n";<br />		echo "发送的内容为:<font color='red'>$in</font> <br>";<br />		<br />	}<br /><br /><br />while($out = socket_read($socket,8192)) {<br />    //echo "接收服务器回传信息成功!\n";<br />	//$obj=json_decode($out); <br />    //echo "接受的内容为:",$out;<br />	echo $out;<br />	//echo $obj->0;<br />}<br /><br /><br />/*<br />if (false !== ($bytes = socket_recv($socket, $buf, 2048, MSG_WAITALL))) {<br />	echo 'aa'.$buf.'aa';<br />    echo "Read $bytes bytes from socket_recv(). Closing socket...";<br />} else {<br />    echo "socket_recv() failed; reason: " . socket_strerror(socket_last_error($socket)) . " ";<br />}<br />*/<br />echo "关闭SOCKET...\n";<br />socket_close($socket);<br />echo "关闭OK\n";<br />?>
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------解决思路----------------------
那不就是 如果一直没有收到终止符 \0、\r、\n 则永远停在等待输入 的情况了
这说明服务端没有发送结束符(也就是没有遵守约定)
你也只能连接 socket_read($socket,1) 的结果了
其实读一块和读一个字节的效率是一样的(都是从输入缓冲区读的)

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