再问红包算法,之前的有bug,@JXYCYFLM,@,该怎么处理

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Release: 2016-06-13 12:17:02
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再问红包算法,之前的有bug,@JXYCYFLM,@
http://bbs.csdn.net/topics/391001579
之前的帖子在此。


两位的算法都是有问题的。

版主给出的修订版,每当红包数量是单数的时候就不对了。加起来不等于总数。


恳请两位大侠帮忙修正。
------解决思路----------------------

$r = distribute(100, 31);<br />echo array_sum($r), PHP_EOL;<br />print_r($r);<br /><br />function distribute($total, $num) {<br />  $avg = $total / $num;<br />  $r = array_fill(0, $num, round($avg, 2));<br /> <br />  for($i=0; $i<$num; $i+=2) {<br />    $t = rand(1, $avg * 100) / 100;<br />    $r[$i] -= round($t, 2);<br />    if($r[$i] <= 0) $r[$i] = 0.01;<br />    if(isset($r[$i+1])) $r[$i+1] += round($t, 2);<br />  }<br />  $r[$num-1] = $total - array_sum(array_slice($r, 0, -1));<br />  return $r;<br />}
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$r = distribute(100, 31);<br />echo array_sum($r), PHP_EOL;<br />print_r($r);<br /><br />function distribute($total, $num) {<br />  $avg = round($total / $num, 2);<br />  $r = array_fill(0, $num, $avg);<br /> <br />  for($i=0; $i<$num; $i+=2) {<br />    $t = rand(1, $avg * 100) / 100;<br />    $r[$i] -= $t;<br />    if($r[$i] <= 0) $r[$i] = 0.01;<br />    if(isset($r[$i+1])) $r[$i+1] += $t;<br />  }<br />  $r[$num-1] = $total - array_sum(array_slice($r, 0, -1));<br />  return $r;<br />}
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------解决思路----------------------
<br />function distribute($total,$num){<br />	return _distribute($total,$num,$total/$num/2,0);<br />}<br />function _ceil($i){<br />	return ((int)($i*100))/100;<br />}<br />function _distribute($total,$num,$pj,$last_c){<br />	if($num==0){<br />		return array();<br />	}<br />	else if($num==1){<br />		return array($total);<br />	}<br />	else {		<br />		$cz=_ceil(mt_rand(-$pj*100,$pj*100)/100);<br />		$n=_ceil($pj+$cz+$last_c);<br />		$res[]=$n;<br />		if($num-1>=0)<br />		$res=array_merge($res,_distribute($total-$n,$num-1,$pj,$pj-$cz));<br />		return $res;<br />	}<br />}<br />$ary=distribute(50,12);<br />print_r(array_sum($ary));<br />print_r($ary);<br />
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------解决思路----------------------
奉上娱乐型红包代码

<br />function fn($total, $part, $min = 0.01) {<br />	$res = array_fill(0, $part, $min);<br />	$total -= $part * $min;<br />	for($i=0; $i<$part; $i++) $total -= ($res[$i] += round($i == $part - 1 ? $total : (rand(0, $total * 100)) / 100, 2)) - $min;<br />	return $res;<br />}<br />
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