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急请高手指导关于Mysqli的prepare出错有关问题

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Release: 2016-06-13 12:24:35
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急!!!请高手指导关于Mysqli的prepare出错问题
很久没写程序了,由于php5.0升级的mysqli类操作数据库有很多优点,本人想尝试用mysqli的方法操作数据库,经过从网上查资料、看手册,浏览、删除都能正常实现,唯独插入功能总是提示错误:Fatal error: Call to a member function prepare() on null in D:\xampps\htdocs\txl\addbook.php on line 20  。
快愁死我了,难道这个问题解决不了我要放弃Mysqli吗?请高手指点我的代码错在哪里?还是服务器的问题?(服务器我用的是Xampps1.9.7集成环境)

if($_POST['contacts'] == "true")
{
    $stmt = $mysqli->prepare("INSERT INTO contactsuser(bookUname, bookDep, bookDuty,bookphone,bookTel,bookEmail,bookGid) VALUES (?, ?, ?, ?, ?, ?, ?)");
    $stmt->bind_param('sssd', $bookUname, $bookDep, $bookDuty, $bookphone, $bookTel, $bookEmail, $bookGid);

    $bookUname = $_POST['bookUname'];
    $bookDep = $_POST['bookDep'];
    $bookDuty = $_POST['bookDuty'];
    $bookphone = $_POST['bookphone'];
    $bookTel = $_POST['bookTel'];
    $bookEmail = $_POST['bookEmail'];
    $bookGid = $_POST['bookGid'];

    /* execute prepared statement */
    $stmt->execute();
    printf("%d Row inserted.\n", $stmt->affected_rows);
    /* close statement and connection */
    $stmt->close();
    exit;
}
------解决思路----------------------
$mysqli 不是 mysqli 对象
------解决思路----------------------
试试面向过程风格的方法:

$stmt = mysqli_prepare($link, "INSERT INTO contactsuser(bookUname, bookDep, bookDuty,bookphone,bookTel,bookEmail,bookGid) VALUES (?, ?, ?, ?, ?, ?, ?)")
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------解决思路----------------------
mysqli_stmt_bind_param($stmt,'ssssssd', $bookUname, $bookDep, $bookDuty, $bookphone, $bookTel, $bookEmail, $bookGid);
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http://php.net/manual/zh/mysqli-stmt.bind-param.php

The number of variables and length of string types must match the parameters in the statement.

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