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PHP实现MySQL更新记录的代码

Jun 13, 2016 pm 12:28 PM
mysql php one time code Revise list accomplish Ideas operate data of choose need first


 首先梳理一下操作思路:

列出所有数据 
选择需要修改的数据记录,进入可编辑状态。 
提交修改结果完成修改
    先列出数据库中的数据view.php,并在每条记录前添加一个modify字样,这样用户就可以选择自己要修改的记录进行修改。

复制代码 代码如下:


$link=mysql_connect("localhost","root","管理员密码"); 
mysql_select_db("infosystem", $link); 
$q = "SELECT * FROM info"; 
mysql_query("SET NAMES GB2312"); 
$rs = mysql_query($q, $link);  

echo "

"; 
echo ""; 
while($row = mysql_fetch_row($rs)) echo ""; 
echo "
部门名称 员工姓名 PC名称
modify $row[1] $row[2] $row[3] $row[4] $row[5] $row[6] $row[7] $row[8] $row[9] $row[10] $row[11] $row[12] $row[13]
"; 
?> 

    

当用户点击modify后,进入相应记录的可编辑状态modify_do.php: 

复制代码 代码如下:



$link =mysql_connect("localhost","root","管理员密码"); 
if(!$link){die("error");} 
echo "连接mysql成功"; 
mysql_select_db("infosystem", $link); 
$del_id=$_GET["id"]; 
$q="select * from info where id=$del_id"; 

mysql_query("SET NAMES GB2312");    //代码转化 
$rs = mysql_query($q, $link); 
if(!$rs){die("没有显示结果");} 
?> 

 

 
 
 

 

echo ""; 

while($row = mysql_fetch_object($rs)) echo "ename'>"; 

mysql_close($link);  //关闭数据集 

?> 

 
 
 
 

    最后,处理提交数据modify_finish.php:

复制代码 代码如下:



$link =mysql_connect("localhost","root","管理员密码"); 
if(!$link){die("error");} 
echo "连接mysql成功"; 
mysql_select_db("infosystem", $link); 

mysql_query("SET NAMES GB2312"); 

$rs = mysql_query($q,$link); 
$row = mysql_fetch_object($rs); 
$exec="update info set ename='".$_POST['ename']."' where id=".$_POST['id'].""; //修改数据并加入最后更新时间 

echo "修改成功!" ; 

mysql_close($link);  //关闭数据集 

?>


作者:Sunec
原载:Cenus Blog
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