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PHP 怎么获取jsonp传的数组

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Release: 2016-06-13 12:30:10
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PHP 如何获取jsonp传的数组

本帖最后由 zl2727 于 2014-01-09 14:19:55 编辑
  var urlstr = "{GID:'" + $("#hogid").val() + "',Name:'" + $("#txtName").val() + "',ProvinceID:'" + $("#ProvinceID").val() + "',CityID:'" + $("#CityID").val() + "',AreaID:'" + $("#AreaID").val() + "',Moblie:'" + $("#txtMobile").val() + "',Address:'" + $("#txtAddress").val() + "',PayType:'" + itemvalue + "'}";<br />
    $.ajax({<br />
        url: "http://www.xxx.com/car.php",<br />
        type: "POST",<br />
        data: urlstr,<br />
		async:false,<br />
		dataType:'jsonp',<br />
		jsonp: "callback",<br />
		jsonpCallback:"getgoods", <br />
        success: function (data) {<br />
          alert(data.res);<br />
        },<br />
        error: function (err) {<br />
            alert("网络加载繁忙,请刷新!");<br />
        }<br />
    });
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如何获取到 data
我的PHP文件中
$urlstr = $_POST;<br />
echo $urlstr.Name;<br />
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什么都没有  应该如何编写?
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