继续求教正则表达式有关问题

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Release: 2016-06-13 12:45:02
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继续求教正则表达式问题

<br />
$str = "昨天 @测试 hiaaaa dd@测试 反反复复";<br />
$reg = "/([^@]+(?=\s))/";<br />
$arr = preg_split($reg,$str,-1,PREG_SPLIT_DELIM_CAPTURE | PREG_SPLIT_NO_EMPTY );<br />
print_r($arr);<br />
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结果是
Array ( [0] => 昨天 [1] => @ [2] => 测试 [3] => hiaaaa [4] => dd@ [5] => 测试 [6] => 反反复复 ) 
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想要的结果是

Array ( [0] => 昨天 @ [1] => 测试 [2] => hiaaaa dd@ [3] => 测试 [4] => 反反复复 ) 
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求教该如何修改正则?

==============
其实就是想把类似于微博里边@功能用正则来拆出@的人,规则是"@开头+人名+空格"不如此的话 有没有其他更好的实现方法?

如果用这个 类似于
$str = "昨天 @测试 hiaaaa dd@测试 反反复复@好友2";
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这样在末尾@了好友,但是没有空格能否用正则判断?
正则表达式

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