jquery的ajax用get步骤无法将值传到后台,why?
jquery的ajax用get方法无法将值传到后台,why??????
如题:
//以下是js的方法
function login() {
$.ajax({
type: "get",
url:'valid.php',
data:"username=admin",
dataType:"json",
success:ajaxComplete(result),
error:ajaxError(response)});
});
}
//以下是valid.php
echo $_GET['username'];
?>
触发login()方法后,页面报错 Notice: Undefined index: username,意思是找不到这个参数,这是为什么呢,求解!!
------解决方案--------------------
你连 js 都写错了,怎么可以得到结果?
function login() {<br /> $.ajax({<br /> type: "get",<br /> url:'valid.php', <br /> data:"username=admin", <br /> dataType:"json", <br /> success:ajaxComplete, <br /> error:ajaxError<br /> });<br /> }<br />
success 和 error 需要的都是回调函数
你要么赋予函数名,要么直接定义匿名函数

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