JS delayed loading (setTimeout) JS is loaded last_javascript skills

First JS lazy loading

Copy code The code is as follows:

<script> <br> setTimeout("document.getElementById('my').src='include/common.php'; ",3000);//Delay 3 seconds <br> </script>

Under normal circumstances, setTimeout is used to achieve
The second JS is loaded last
Insert the following code where JS needs to be inserted:

Copy code The code is as follows:

LOADING...

Of course, that LOADING... you can change it to a small picture you like. It looks very AJAX effective.
Then insert at the bottom of the page:

Copy code The code is as follows:

js code

Copy code The code is as follows:

<script>L4EVER.innerHTML=AD_L4EVER.innerHTML;AD_L4EVER.innerHTML="";</script>

The standard syntax of setTimeout is: setTimeout(expression, time (milliseconds)) two parameters.

Here, focus on the call when the first parameter is a function, assuming it is a function.

1. Function without parameters:
function alertV(){ alert("000"); }

When the first parameter is not quoted ("" or ''), there is a one second delay:
setTimeout(alertV,1000);

When the first parameter is quoted, delay for one second:
setTimeout("alertV()",1000);


2. The function has parameters:

function alertV(event){ alert("keyCode=" event.keyCode); }

At this time it should be set to:
setTimeout(function(){alertV(event);},1000); Otherwise, it will prompt that the parameter is undefined.

setTimeout(function () {
    $("#id").html(datastr);
  }, 1000);

jquery is implemented through delay, such as

$("#id").delay(1000).html(datastr);

setTimeout('yourFunction()',5000); Execute yourFunction() after 5 seconds, only once
setInterval('yourFunction()',5000); Execute u
every 5 seconds
If setTimeout('yourFunction()',5000) is called again in yourFunction(), you can complete something similar to

The function of setInterval('yourFunction()',5000)

If anyone has a better and feasible method, thank you for sharing.