php中form表单的值用submit提交后，如何在上个页面取出来
php中form表单的值用submit提交后，怎么在下个页面取出来
我的php文件里有复选框checkbox的值，选择了用form表单的submit来提交值，想在数据提交后，将其和下个页面的数据一起用socket发出去。但是submit的数据在用socket发的时候值取不出来。目前session和cookie都不可用。我是新手，希望有专家可以帮忙解决下哈。
------解决方案--------------------
print_r($_POST);
------解决方案--------------------
不知道是否我理解错了，楼主的左面选择的和右面显示的数据应该在一个表吧，或者说右面的数据表中肯定有左面的选择设备，再者左右也应该有对应关系，直接在右面的form提交个
------解决方案--------------------
没太看明白楼主的意思，如果仅是checkbox取值的话
假设checkbox都是这样
123
后几个省略掉
提交到另一个页面后，在获取值的方法
$zixun1 = $_POST['zixun1'];
for($i=0;$i
";
?>
?>
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