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javascript regular replacement replace(regExp, function) usage_javascript skills



javascript regular replacement replace(regExp, function) usage_javascript skills
May 16, 2016 pm 06:26 PM
javascript
Copy code The code is as follows:
function fn()
{
for(var i = 0;i < arguments.length;i ){
alert("The value of the" (i 1) "th parameter: " arguments[i]);
}
}
var str = '<div id="{wo}" >{ni}</div>';
str.replace(/{([a-z] )}/ig, fn);
According to the output results of multiple tests, it can be concluded that in fn:
The first parameter is the matched string, such as {wo} and {ni};
The second parameter can have 0-N, which matches a bracketed regular string in the first parameter. For example, wo and ni in the first parameter can match ([a-z] ),
There are several groups of brackets, and there are several parameters;
The third parameter is the position of the string matched in the first parameter, such as {wo} returns 9, {no} returns 16;
The fourth parameter is the string used to match, in this example it is <div id="{wo}" >{ni}</div>.
In this example, for a json object containing wo and ni, you can simply use:
Copy code The code is as follows :
str.replace(/{([a-z] )}/ig, function(s, t){
return json[t];
});
to replace.
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