javascript regular replacement replace(regExp, function) usage_javascript skills

Copy code The code is as follows:

function fn()
{
for(var i = 0;i < arguments.length;i ){
　alert("The value of the" (i 1) "th parameter: " arguments[i]);
　}
}
var str = '<div id="{wo}" >{ni}</div>';
str.replace(/{([a-z] )}/ig, fn);

According to the output results of multiple tests, it can be concluded that in fn:

The first parameter is the matched string, such as {wo} and {ni};

The second parameter can have 0-N, which matches a bracketed regular string in the first parameter. For example, wo and ni in the first parameter can match ([a-z] ),

There are several groups of brackets, and there are several parameters;

The third parameter is the position of the string matched in the first parameter, such as {wo} returns 9, {no} returns 16;

The fourth parameter is the string used to match, in this example it is <div id="{wo}" >{ni}</div>.

In this example, for a json object containing wo and ni, you can simply use:

Copy code The code is as follows :

str.replace(/{([a-z] )}/ig, function(s, t){
return json[t];
});

to replace.