sql like 查询有关问题

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Release: 2016-06-13 13:19:56
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sql like 查询问题
$sql = select * from `sys_barcode_1d_temp` where date LIKE '2012-07-26%';

数据库里面有数据,为什么值查询不出来?

date字段格式是 Y-m-d H:i:s

------解决方案--------------------
date 是字符串还是日期格式?
------解决方案--------------------
在哪里执行的?

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