自个儿动手写 PHP acts_as_taggable_on 实现
自己动手写 PHP acts_as_taggable_on 实现
只好 参阅rails的acts_as_taggable_on 说白了 核心就一个sql
select post.*,count(tag.id) as count
from post,tag,taging
where post.id!={当前post.id} #排除自身
and post.id=taging.post_id #限定标签的范围为当前post所拥有的标签集合
and taging.tag_type=post.base_class #限定标签类型为当前post的基本类型
and taging.tag_id=tag.id #限定必须是有效的标签
and tag.name in ({当前post拥有的标签})
group by post.id
order by count desc
鄙视 某些人 教程说完一半后面就没了...
简单的东西都复杂话了 ?

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