JS里面嵌入php代码,JS语法异常了,请大家帮小弟我看看
JS里面嵌入php代码,JS语法错误了,请大家帮我看看
for(var j=0; j; j++){
if(oSize.value == ''){
oSize.selected = true;
}
}
问题就出在这句话。oSize.value == '
错误代码是:Undefined index: j in
没有变量j,这个j并不是PHP变量,他是一个js变量,怎么让它嵌入在php里面。
请大家帮帮忙。
------解决方案--------------------
不可能的
你的 $Size 显然是一个数组JScript code
var Size = ['<?php join("'", $Size) ?>'];
for(var j=0; j<size.length j if size osize.selected="true;"></size.length><font color="#e78608">------解决方案--------------------</font><br>一个运行在前端 一个运行在后端 怎么能这样写在一起呢?<br>把$Size 转化成json对象赋值给js变量 然后交给js处理就好了 <div class="clear">
</div>

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