调试有关问题呀

WBOY
Release: 2016-06-13 13:31:31
Original
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调试问题呀
[code=PHP][/code]
include("conn.php");
$ip=$_SERVER['REMOTE_ADDR'];
$result=mysql_query("select * from ip where id=$_GET[id] ",$conn )or die(mysql_error());
if($ip=iip){

echo "shibei>";

}else{
mysql_query("insert into ip(id,iip) values(null,'$ip')",$conn)or die(mysql_error());
}
 ?>
这个对吗?我想判断的是当ip表中的id等于一个数例如等译id=4时对应着的iip这个值是否等于$ip这个值,我这样写好像是判断不了呀,我应该怎么写呀,调试了好大一会儿了 没有办法了

------解决方案--------------------
include("conn.php");
$ip=$_SERVER['REMOTE_ADDR'];
$result=mysql_query("select * from ip where id=$_GET[id] ",$conn )or die(mysql_error());
$row=mysql_fetch_assoc($result);
if($ip==$row['iip']){

echo "shibei>";

}else{
mysql_query("insert into ip(id,iip) values(null,'$ip')",$conn)or die(mysql_error());
}
 ?>
------解决方案--------------------
if($ip=iip){ 这是毛啊

if ($result === false || mysql_num_rows() == 0) {
echo "shibai
";
} else {
$result = insert.....
if ($result === false) {
//说明在select与insert之前有其他进程插入了此IP,也应该返回失败。
//要求数据库中IP字段建唯一索引
}
}
------解决方案--------------------
[Quote=引用:]
[code=PHP][/code]
include("conn.php");
$ip=$_SERVER['REMOTE_ADDR'];
$result=mysql_query("select * from ip where id=$_GET[id] ",$conn )or die(mysql_error());
if($ip=iip){ //这个是???

echo "shibei>";
……
[/Quote]
$ip=iip ,这个ipp应该是变量吧!根源应该就在这里了!

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