请问:php输出div为何不显示
请教:php输出div为何不显示?
- PHP code
<!-- Code highlighting produced by Actipro CodeHighlighter (freeware) http://www.CodeHighlighter.com/ --> <?php if(!isset($_POST['username'])) { header("location: index.php"); } if (!$_POST['name']) error("请输入名称"); if (!$_POST['name']) error("请输入姓名"); if (!$_POST['username']) error("请输入账号"); if (!$_POST['password']) error("请输入密码"); $link = @mysql_connect($db_host, $db_user, $db_pwd) or die("无法连接资料库<br>" . mysql_errno() . " " . mysql_error()); mysql_query("SET NAMES '$charset'"); mysql_select_db($db_name, $link) or die("无法进入资料库$db_name"); $sql = "SELECT * FROM uc_members where username='$_POST[username]'"; if (mysql_num_rows(mysql_query($sql, $link)) != 0) error("此账号已经被注册"); $sql = "INSERT INTO uc_members(bbsname,bbstype,name,username,password,email,regtime,regip,phone,idnumber,address,ps) VALUES('$_POST[bbsname]','$_POST[bbstype]','$_POST[name]','$_POST[username]','".md5($_POST['password'])."','$_POST[email]','".date("Y-m-d H:i:s",time()+$time_ctrl*3600)."','$_SERVER[REMOTE_ADDR]','$_POST[phone]','$_POST[idnumber]','$_POST[address]','')"; $result = @mysql_query($sql, $link) or die("无法新增记录<br>" . mysql_errno() . " " . mysql_error()); mysql_close($link); $html = file_get_contents("$html_dir/reg_ok.htm"); echo preg_replace("/\\$([a-z0-9\_]+)/sie","$\\1", $html); $username=$_POST['username']; $password=$_POST['password']; $name=$_POST['name']; $phone=$_POST['phone']; $idnumber=$_POST['idnumber']; $address=$_POST['address']; $email=$_POST['email']; $copy = $_POST['username']; $countFile = 0; $countDir = 0; function copyDir($dirFrom,$dirTo){ global $countFile; global $countDir; if(is_file($dirTo)){ die("创建失败!"); }elseif(is_dir($dirTo)){ die(" 此 $dirTo 账号已有人申请:请回到<a href="javascript:history.back();">上一页</a>重新输入用户名!"); }elseif(!is_dir($dirFrom)){ die(" $dirFrom 不存在!"); }else{ if(!mkdir($dirTo)){ die("发生未知错误,$dirTo 建立失败!有可能权限不足!"); } $countDir++; } $handle = opendir($dirFrom); while(($file_name = readdir($handle))!==false ){ $file_path_from = $dirFrom.DIRECTORY_SEPARATOR.$file_name; $file_path_to = $dirTo.DIRECTORY_SEPARATOR.$file_name; if($file_name!="." && $file_name!=".."){ if(is_dir($file_path_from)){ copyDir($file_path_from,$file_path_to); }else{ if(!copy($file_path_from,$file_path_to)){ die("$file_path_from的时候发生未知错误,有可能权限不足!"); } $countFile++; } } } closedir($handle); } copyDir("client","$copy"); echo "<div class='\"main_center' minwidth> <div class='\"main_middle\"'> <div class='\"main_checking\"'> <div class='\"main_checking01\"'> <div class='\"main_checking01fl\"'></div> <div class='\"main_checking01f\"'> <div class='\"main_checking01fr_title\"'>创建成功:建立 $countFile 个文件!</div> </div> </div> </div> </div> </div>"; ?>
为什么这段不能显示呢?
- PHP code
<!-- Code highlighting produced by Actipro CodeHighlighter (freeware) http://www.CodeHighlighter.com/ --> echo "<div class='\"main_center' minwidth> <div class='\"main_middle\"'> <div class='\"main_checking\"'> <div class='\"main_checking01\"'> <div class='\"main_checking01fl\"'></div> <div class='\"main_checking01f\"'> <div class='\"main_checking01fr_title\"'>创建成功:建立 $countFile 个文件!</div> </div> </div> </div> </div> </div>"; <div class="clear"> </div>

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