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求教一个PHP赋值判断的有关问题

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Release: 2016-06-13 13:38:03
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求教一个PHP赋值判断的问题
刚刚接触PHP,在一个MYSQL的类当中看到这么一句话
$condition = $condition ? 'where' .$condition :NULL
不是太明白什么意思,请教大家能否解释一下。
我个人是把他理解成:如果'where'.$condition为空,则把'where'.$condition赋值给$condition,反之,则把$condition=$condition,不懂是对还是错,还望大神前来指教!!

------解决方案--------------------
靠!楼上错了!

如果'where'.$condition为空,则把'where'.$condition赋值给$condition,反之,则把$condition=$condition

=>

如果$condition不为空,则把'where'.$condition赋值给$condition,反之,则把$condition=NULL
------解决方案--------------------
这是拼合一个SQL语句。
例如 如果用户没有设置匹配条件,那么就是
SELECT * FROM tablename;
如果有设置条件,即$condition不为空的话
SELECT * FROM tablename WHERE $condition;
------解决方案--------------------
$a ? $b : $c 
php 的三元运算符。
如果$a 为 true 表达式的值为$b,如果为 false 则表达式值为$c.
------解决方案--------------------

PHP code

$condition = $condition ? 'where' .$condition :NULL

//等同于
if($condition){
  $condition = 'where' .$condition;
}else{
  $condition = NULL;
} <div class="clear">
                 
              
              
        
            </div>
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