Home Backend Development PHP Tutorial 问sql查询的有关问题,与昨天相同请jordan102进来一下

问sql查询的有关问题,与昨天相同请jordan102进来一下

Jun 13, 2016 pm 01:42 PM
null quot user

问sql查询的问题,与昨天相同请jordan102进来一下!
我用select * from user_list where user_id in (883985,883987,802928,802929);
查询结果只有一行返回值,不是四行,请教你有没有在php环境下用这个sql语句做过测试,谢谢

命令行下的查询结果
=============================================================
| 802928 | fnms | fnms | NULL | 非你莫属 |
| 802929 | xwei | xwei | NULL | 校尉 |
| 883985 | gggef | gggef | NULL | gggef |
| 883987 | eeett | eeett | NULL | eeett |


在php页面中

$newsql = "select * from user_list where user_id in (883985,883987,802928,802929)";
$rsList= mysqli_query($conn,$newsql)
while($row = mysqli_fetch_array($rsList))
{
echo "
-------------user_id:".$row["user_id"];
}
以下是打印结果
==========================================================================================
-------------user_id:802928

------解决方案--------------------
首先把sql语句在命令行下或phpmyadmin下执行一下,看结果对不对。

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