php如保得到类名和方法名?该如何处理

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Release: 2016-06-13 13:42:31
Original
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php如保得到类名和方法名?
class a{
function b{
//如果在这里打印出a_b呢?
}
}

------解决方案--------------------
class a{
function b{
 echo __CLASS__ . "_" . __METHOD__;
}
}
------解决方案--------------------
可以尝试这样

PHP code

class a{
    function  b($functionName){   
        echo get_class($this).'_'.$functionName;
    }   
} 

class   c   extends   a 
{ 
    function   d(){ 
       $this->b(__FUNCTION__); 
    } 
}
$c = new c();
$c->d();
<br><font color="#e78608">------解决方案--------------------</font><br>不用参数也可以的<br>class a{<br>   var $v = '';<br>   function b(){<br>       echo "<br>" . get_class($this).'_'.$this->v;<br>   }<br>}<br><br>class c extends a<br>{<br>   function d(){<br>      $this->v = __FUNCTION__;<br>      $this->b();<br>   }<br>}<br>$c = new c();<br>$c->d();
<br><font color="#e78608">------解决方案--------------------</font><br>嗯,又学到东西了,3Q了 <div class="clear">
                 
              
              
        
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