关于mysql添加数据,该如何处理

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Release: 2016-06-13 13:44:40
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关于mysql添加数据
INSERT INTO room (roomid,name,id1,id2)values('1','232','$_POST[id1]','$_POST[id2]')

$_POST[id1],$_POST[id2] 传过来的是值,不是ID,这里怎么处理下啊?

------解决方案--------------------
$_POST[id1],$_POST[id2] 传过来的是值不是id是怎么个概念。

是不是sql中的值是变量名,不是值啊。 
INSERT INTO room (roomid,name,id1,id2)values('1','232','{$_POST[id1]}','{$_POST[id2]}')

or

"INSERT INTO room (roomid,name,id1,id2)values('1','232','".$_POST[id1]."','".$_POST[id2]."')"
------解决方案--------------------
什么意思??
------解决方案--------------------
两张表的id不能在一个insert语句中同时插入,要分步进行。
id若设为auto_increment,那么不用插id,而且不能插入重复值。
若没有设为自增长:
sql = "insert into room(roomid,name,id1) values(".$_POST['roomid'].",'".$_POST['name']."',".$_POST['id1'].")";
查询时,进行多表查询就可以了。

------解决方案--------------------
$_POST[id1],$_POST[id2] 本来就他的value

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