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高手们 急救 多谢啦.在线

Jun 13, 2016 pm 01:45 PM
quot string

高手们 急救 谢谢啦...在线
代码如下 我想加入inseeCode同时赋值给string 并将inseeCode以(inseeCode)形式在ncc后面一起显示 应该如何更改:
我已经把inseeCode形式写出来了为$informal


while($row= mysql_fetch_array($result)){
$informal = (!empty($row[inseeCode]) ? ' ('.$row[inseeCode].')' : '');
$a.=$row[ncc]$informal.',';
}
$string="$a";

------解决方案--------------------
两个变量之间用连接符点.连接
------解决方案--------------------
lz是不是新学php啊?发现你基本语法不会用
------解决方案--------------------
不应该啊,你把错误提示打开,看报什么错误
------解决方案--------------------

探讨

引用:

$a.=$row[ncc].$informal.',';
一运行就没有反应了 不知道什么情况 数据库信息挺大的有3万多信息

------解决方案--------------------
不客气,问题解决了那我就可以回家了,呵呵
------解决方案--------------------
我猜楼主是女的.....

随便回答问题: 要看你的字段名是不是写对了...
------解决方案--------------------
探讨

引用:

我猜楼主是女的.....

随便回答问题: 要看你的字段名是不是写对了...
麻烦你能说的详细点吗 还有个小问题 就是怎么将$a转化成纯数字 我从数据库输出了$a 在后台echo $a 得到的是个数字 在php里面我想把它赋值给
  • 里面的id 应该怎么处理呢 谢谢

  • ------解决方案--------------------
    那就改成

  • 或者



  • 还不行的话,贴全部代码......
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