高手们 急救 多谢啦.在线
高手们 急救 谢谢啦...在线
代码如下 我想加入inseeCode同时赋值给string 并将inseeCode以（inseeCode）形式在ncc后面一起显示 应该如何更改：
我已经把inseeCode形式写出来了为$informal
while($row= mysql_fetch_array($result)){
$informal = (!empty($row[inseeCode]) ? ' ('.$row[inseeCode].')' : '');
$a.=$row[ncc]$informal.',';
}
$string="$a";
------解决方案--------------------
两个变量之间用连接符点.连接
------解决方案--------------------
lz是不是新学php啊？发现你基本语法不会用
------解决方案--------------------
不应该啊，你把错误提示打开，看报什么错误
------解决方案--------------------
------解决方案--------------------
不客气，问题解决了那我就可以回家了，呵呵
------解决方案--------------------
我猜楼主是女的.....
随便回答问题: 要看你的字段名是不是写对了...
------解决方案--------------------
------解决方案--------------------
那就改成
或者
还不行的话,贴全部代码......
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