php变量访问 不懂
php变量访问 不懂求助
- PHP code
<!-- Code highlighting produced by Actipro CodeHighlighter (freeware) http://www.CodeHighlighter.com/ --> <?php $my_var = "abc"; function my_fun() { echo $my_var; } my_fun(); ?>
在函数内部为何不能访问函数外面的变量
函数内部的变量是局部变量
函数外面的是全局变量 按理说应该在函数内部能访问外面的变量
为何函数内部提示:the local variable $my_var may not have been initialized
求大牛高手帮忙解说下,不甚感激!
------解决方案--------------------
在函数内部为何不能访问函数外面的变量 ---可以方问函数外部的全局变量,
函数内部的变量是局部变量
函数外面的是全局变量 按理说应该在函数内部能访问外面的变量 --是可以访问的
为何函数内部提示:the local variable $my_var may not have been initialized
求大牛高手帮忙解说下,不甚感激!
$my_var = "abc";
global $my_var = "abc";
------解决方案--------------------
global $my_var;
$my_var = "abc";
------解决方案--------------------
- PHP code
<?php global $my_var; $my_var='abc'; function my_fun() { global $my_var; echo $my_var; } my_fun(); ?> <br><font color="#e78608">------解决方案--------------------</font><br>你可以这么理解,函数内和函数外是两个世界,两个世界时间变量默认是不认识的,只有介绍了才有机会认识,介绍方法就是global。<br><br>
- PHP code
<?php $a = 'abc'; function aaa() { echo $a; //这个你可以写成$GLOBALS['aa'], 也可以在这语句上面global $a; } ?> <br><font color="#e78608">------解决方案--------------------</font><br>要设置成全局变量的, <br><font color="#e78608">------解决方案--------------------</font><br>我测式了成功后在发出来的代码。<br>
------解决方案--------------------
在函数外面的变量前面+global 毛用不起
函数外面的变量就是全局变量了已经,+global有毛用
函数里面的变量加global才是全局变量,这样设计就是为了容易区分和理解,况且手册上例子举的的很明白
http://www.php.net/manual/zh/language.variables.scope.php
------解决方案--------------------
------解决方案--------------------
$a = 'abc';
function aaa() {
echo $a; //这个你可以写成$GLOBALS['aa'], 也可以在这语句上面global $a;
}
?>

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