python实现获取序列中最小的几个元素

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Release： 2016-06-16 08:41:42

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本文实例讲述了python实现获取序列中最小的几个元素。分享给大家供大家参考。

具体方法如下：

import heapq 
import random 
def issorted(data): 
 data = list(data) 
 heapq.heapify(data) 
 while data: 
  yield heapq.heappop(data) 
   
alist = [x for x in range(10)] 
random.shuffle(alist) 
print 'the origin list is',alist 
print 'the min in the list is' 
for x in issorted(alist): 
 print x,

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程序运行结果如下：

the origin list is [2, 3, 4, 9, 8, 5, 1, 6, 0, 7]
the min in the list is
0 1 2 3 4 5 6 7 8 9

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使用了heapq模块和random模块.heapq二叉树，常用来处理优先级序列问题。

此外还有一个更为简单的方法：

print heapq.nsmallest(3,alist)　#打印出alist列表中最小的三个元素最小,如果是字母就是按字母序比较

感兴趣的朋友可以测试运行本文实例，相信本文所述对大家Python程序设计的学习有一定的借鉴价值。

Related labels：

python element sequence smallest Obtain

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