Python 不同对象比较大小示例探讨-Python Tutorial-php.cn

万恶的源泉：

Fireboo的疑问（当然 lambda 本身写的就有问题）：

>>> filter( lambda x: x > 2, [ 1, [ 1, 2, 3 ], 2, 3 ] ) 
[[1, 2, 3], 3]

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？：

>>> 1 < [ 1 ] 
True 
>>> int < list 
True 
>>> dict < int < list 
True

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>>> int < map 
False

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后来几经周折，和 Fireboo 讨论了下，是

1.不同对象比较（除了 number 之外），是按照 type names 比较，

2.当相同类型对象不支持适当比较的时候，采用 address 比较

3.list 与 list， tuple 与 tuple 采用字典序比较

>>> x = 1 
>>> y = [ 1 ] 
>>> type( x ) 
<type 'int'> 
>>> type( y ) 
<type 'list'> 
>>> x < y 
True

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>>> type( int ) 
<type 'type'> 
>>> type( list ) 
<type 'type'> 
>>> id( int ) 
505552912 
>>> id( list ) 
505555336 
>>> int < list 
True

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>>> type( map ) 
<type 'builtin_function_or_method'> 
>>> type( list ) 
<type 'type'> 
>>> map < list 
True

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Related labels：

python object Comparison of size

source：php.cn

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