Python中的CURL PycURL使用例子

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Release: 2016-06-16 08:44:02
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在Linux上有个常用的命令 curl(非常好用),支持curl的就是大名鼎鼎的libcurl库;libcurl是功能强大的,而且是非常高效的函数库。libcurl除了提供本身的C API之外,还有多达40种编程语言的Binding,这里介绍的PycURL就是libcurl的Python binding。
在Python中对网页进行GET/POST等请求,当需要考虑高性能的时候,libcurl是非常不错的选择,一般来说会比liburl、liburl2快不少,可能也会比Requests的效率更高。特别是使用PycURL的多并发请求时,更是效率很高的。个人感觉,其唯一的缺点是,由于是直接调用的是libcurl C库,PycURL的函数接口之类的还和C中的东西很像,可能不是那么的Pythonic,写代码的学习曲线稍微比liburl高一点儿。
还是看个简单的例子吧:

复制代码 代码如下:

#! /usr/bin/env python
# -*- coding: utf-8 -*-

'''
Created on Dec 15, 2013

@author: Jay
'''

import sys
import pycurl
import time

class Test:
    def __init__(self):
        self.contents = ''

    def body_callback(self, buf):
        self.contents = self.contents + buf

sys.stderr.write("Testing %s\n" % pycurl.version)

start_time = time.time()

url = 'http://www.dianping.com/shanghai'
t = Test()
c = pycurl.Curl()
c.setopt(c.URL, url)
c.setopt(c.WRITEFUNCTION, t.body_callback)
c.perform()
end_time = time.time()
duration = end_time - start_time
print c.getinfo(pycurl.HTTP_CODE), c.getinfo(pycurl.EFFECTIVE_URL)
c.close()

print 'pycurl takes %s seconds to get %s ' % (duration, url)

print 'lenth of the content is %d' % len(t.contents)
#print(t.contents)
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