表单get传参是怎么包装URl的?
如图 这是正常的表单get提交 参数是时间格式 2016-5-12 参数在提交时候自动转化了 在action文件那边直接$_get 就获取正常数据:2016-5-12 php有没有类似的函数 现在我想用a链接传参时间 由于url设置问题一直都是只获取2016 现在不想用urlencode()等函数 也不想转成时间戳来传 因为在action那边的文件不想加解码或者转换的函数 要怎么样才能实现表单get提交的效果呢??
回复讨论(解决方案)
我的URL分界符就是“ - ” 所以一直都是这样传只能获取为2016 后面的就没了
2016%2F05%2F04 是 2016/05/04 而不是2016-05-04
这样很正常,不需要encode
<a href="server.php?date=2016-05-04">go</a>
<?phpprint_r($_GET['date']);?>

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