如何利用ajax实现赞
在php+mysql 实现赞的方法很简单,每点击一次赞,传入字段(cont_id,cont_type),每次向数据库中like_count自动加1,但是如何利用jquery中的ajax实现呢?
回复讨论(解决方案)
$.ajax({ type:"get", url:"xxxxxxxxxxxxxx.php", data:{ action:"dianzan", //php辨识ajax的标志(这一条不一定要加,看PHP文件结构 uid:"xxxxxxxxxxx", //谁发起了点赞, pid:"xxxxxxxxx", //什么元素被点赞 }, success:function(msg){ //接收PHP返回的信息,是否点赞成功,如果成功,前台JS进行特效转换来提醒用户点赞成功 如果未成功则提示原因等等 }});
建议直接看视频教程
http://www.php100.com/html/shipinjiaocheng/PHP100shipinjiaocheng/2011/0417/7924.html
看了包会
楼上两位都是好人
楼主做出来了吗?可以给我具体的代码参考参考吗?

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