PHP程序header location 进行跳转的注意细节及ie兼容问题！
使用PHP程序header location 进行跳转的注意的一个细节！
众所周知，PHP网站跳转有三种方法：JS、HTML META Refresh、PHP header("location: $url")。但是这里有一个非常小的细节，很容易导致出错。
有一次制作一个跳转程序，结果忽略了这一点，导致跳转其实都是没有成功。
程序全部源码如下，程序地址：http://www.***.com/go.php
<?php error_reporting(7);
$url = urldecode( trim($_REQUEST['url']));
if($url)
{
header("Location: $url");
} else {
exit('Error Input,<a href="http://www.***.com/?f=go.php">go back');
}
当访问地址为：http://www.***.com/go.php?url=http%3A%2F%2Fwww.zbphp.com%2F 的时候，firefox浏览器是正常的。后来把这个跳转程序复制到公司的另外一个网站，让QQ上的一些好友测试，结果很多人都说打不开：IE内核的浏览器直接提示无法访问或者找不到，chrome有时候会提示被重置或找不到，使用firefox测试也偶偶会提示无法找到，但多刷新一次才显示正常。
仔细检查代码，是没有问题的。况且firefox是可以跳转，后想到了以往阅读到的一点就是：IE浏览器如果输出的内容字节太小（小于512字节），那么就会被忽略。然后将源码由header location跳转修改为 js html才所有浏览器都测试通过，原先偶偶出现firefox点击提示找不到xxx服务器也没有再出现过，现go.php全部源码：
<?php error_reporting(7);
function gheader($url)
{
echo '<html><meta http-equiv="Content-Language" content="zh-CN"><meta http-equiv="Content-Type" content="text/html;charset=gb2312"><meta http-equiv="refresh" content="0;url='.$url.'"><title>loading ... </title><div style="display:none">
<script type="text/javascript">var cnzz_protocol = (("https:" == document.location.protocol) ? " https://" : " http://");document.write(unescape("%3Cspan id=\'cnzz_stat_icon_5696423\'%3E%3C/span%3E%3Cscript src=\'" + cnzz_protocol + "s9.cnzz.com/stat.php%3Fid%3D5696423%26show%3Dpic1\' type=\'text/javascript\'%3E%3C/script%3E"));</script>
</div>
<script>window.location="'.$url.'";</script>
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