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Home php教程 php手册 url传递中文字符,特殊危险字符的解决方案(仅供参考)urldecode、base64_encode

url传递中文字符,特殊危险字符的解决方案(仅供参考)urldecode、base64_encode

Jun 21, 2016 am 08:46 AM
array base encode str url

web开发的过程中,当我们需要在url中传递中文字符或是其它的html等特殊字符时,似乎总会碰到各种各样的小问题,因为不同的浏览器对他们的编码又不一样。对于中文,一般的做法是:

把这些文本字符串传给url之前,先进行urlencode($text)一下。

但是对于一些很“危险”的字符,比如说html字符,甚至是SQL注入相关的字符,如果很明显的传给系统,出于安全考虑,系统一般都会把它们过滤掉的。

那么,如果我们需要保留这些危险字符,不被过滤,该这么办呢?

我想到的办法是先给它们 base64_encode($text) 编码,到服务端时,又给它们 base64_decode($text) 解码,

貌似很完美,但是在使用的过程中又遇到一个问题,base64_encode 编码后的字符串中含有 "/", "+", "=" 等字符,

这些字符在url编码中又是特殊字符,比如 "+" ,它就表示 “空格”,但是不同的浏览器对“空格”的编码又不一样,有的是用“+”表示,有的是用“20%”表示,也就是说,让这些base64_encode编码后的字符串在url中传递,用不同的浏览器去浏览时,服务端得到值不一样。

于是乎,想到了一个折中办法,先将这些base64编码后的特殊字符替换掉,到服务端后,又替换回来:

function base_encode($str) {
        $src  = array("/","+","=");
        $dist = array("_a","_b","_c");
        $old  = base64_encode($str);
        $new  = str_replace($src,$dist,$old);
        return $new;
}
 
function base_decode($str) {
        $src = array("_a","_b","_c");
        $dist  = array("/","+","=");
        $old  = str_replace($src,$dist,$str);
        $new = base64_decode($old);
        return $new;
}
Copy after login

下面是在浏览器中得到的效果

xOO6w6Osuf65_aiy_atL_b00Ke5_b8jnus6ho6GjoaM_c

呵呵,看看效果如何。。。

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