一步步编写PHP的Framework(六)
不知道大家注意到没有,之前我们导入一个配置文件是通过include CONFIGS_PATH . '/config.php'来做的,这样做好吗?
不忙回答,我可以提两个问题:
1. 如果这个路径下面的config.php不存在会发生什么现象?
2.如果我将PHP这种配置文件修改成为xml这种配置文件之后会发生什么现象?
首先,如果文件不存在,那么PHP会抛出一个警告,但是程序继续执行;配置文件变成xml之后,入口文件处需要编写相应的读取xml的代码,而且需要把之前的include CONFIGS_PATH . '/config.php'这句代码修改掉。
那么有没有方法能够实现配置文件的无缝切换呢?
在具体讲解这些之前,我首先说一下工厂模式,现假设:A需要购买一辆红色汽车,他直接向B(一个生产汽车的工厂)提出需求,B按照A的需求,从仓库中选取一辆合适的汽车,然后交给A。整个过程,A只是提出需求,具体汽车的选取是由B工厂来确定的,这种方式就是工厂模式。
举个例子:
01 |
02 | public class Factory { |
03 | public static function factory($whichOneToChoose) { |
04 | $returnVal = 'Red'; |
05 | switch($whichOneToChoose) { |
06 | case1 : |
07 | $returnVal = 'Blue'; |
08 | break |
09 | case 2 : |
10 | $returnVal = 'Green'; |
11 | break; |
12 | default : |
13 | break; |
14 | } |
15 | return $returnVal; |
16 | } |
17 | } |
工厂模式一般都有一个静态的方法:factory负责逻辑的处理。
现在我们可以新建一个专门处理配置文件的类:Config.php
01 |
02 | class Config { |
03 | const XML = 1; |
04 | const INI = 2; |
05 | const PHP = 3; |
06 | public static function factory($which) { |
07 | switch($which) { |
08 | caseConfig::XML : |
09 | return XmlConfig::parse(CONFIGS_PATH . '/config.xml'); |
10 | break; |
11 | case Config::INI : |
12 | return IniConfig::parse(CONFIGS_PATH . '/config.ini'); |
13 | break; |
14 | case Config::PHP : |
15 | //此处没有做文件是否存在的判定,你可以自己判定一下,我只是做一个例子 |
16 | return include CONFIGS_PATH . '/config.php'; |
17 | break; |
18 | default: |
19 | return array(); |
20 | break; |
21 | } |
22 | } |
23 | } |
如果你要将配置文件修改成为xml这种方式,只需要在XmlConfig.php中实现即可,当然,为了简单,我在这儿只是实现ini配置文件的编写,xml的配置文件你可以自己去尝试一下,如果你想查看具体实现,可以查看Toper中的/Library/Toper/Config/XmlConfig.class.php的具体代码。
01 |
02 | class XmlConfig { |
03 | public static function parse($file) { |
04 | if(!is_file($file)) { |
05 | throw new Exception('none exists xml config file'); |
06 | } else { |
07 | return parse_ini_file($file,true); |
08 | } |
09 | } |
10 | } |
这个文件的代码是我随手写的,不保证代码的正确性,了解思路即可。

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