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用“类”来代替“递归方法”,用php举例。

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Release: 2016-06-21 09:06:52
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递归

问题:一个楼梯有n个台阶,每次上一个或两个台阶,共有多少种上法, 每种走法的步骤是什么样的?
这个简单问题,我们通常的方法是写一个递归调用,简单明了。但是,这里通过类的叠加来实现,虽然本身没有太大的意义,但是这种设计的用途还是满多的,可以自己考虑考虑。


//一个楼梯有n个台阶,每次上一个或两个台阶,共有多少种上法, 每种走法的步骤是什么样的.
define('TOTLE_STEP', 10);
$p = '';
$obj = new step($p, 0, 0);
$obj->go();

class step{

 var $parent;
 var $count;
 var $step;
 var $son1;
 var $son2;

 function step(&$parent, $step, $count){
        $this->parent = &$parent;
        $this->step = $step;
        $this->count = $count + $step;
 }

 function go(){
  if($this->count==TOTLE_STEP)
   $this->callback();
        if($this->count         $this->son1 = new step($this, 1, $this->count);
         $this->son1->go();
        }
        if($this->count         $this->son2 = new step($this, 2, $this->count);
         $this->son2->go();
        }
 }

 function callback($str=''){
        if($this->parent!=null){
         $str = $this->step.$str;
         $this->parent->callback('--'.$str);
        }else{
         echo $str.'
';
        }
 }
}
?>



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