利用PHP语言读取数据库数据的实例
数据|数据库
在学习《十天学会PHP》的过程中,当看到关于数据库连接的问题时,由于知识的不足,遇到了困难。于是找朋友帮忙写了个PHP小程序,在这里贴出来,希望对大家能有帮助。注释是我自己写的。
这段代码的功能是:
连接到一个 url 地址为localhost 、 端口为 3306 的mysql服务器上。mysql服务器的帐号是"root",密码是"9999"。mysql 服务器上有一个数据库 ok , 数据库里有一个表 abc。表 abc 一共为两列,列名分别是 "id" 和 "name" ,将 abc 里的所有数据读出来。
$dbh = @mysql_connect("localhost:3306","root","9999");
/* 定义变量dbh , mysql_connect()函数的意思是连接mysql数据库, "@"的意思是屏蔽报错 */
if(!$dbh){die("error");}
/* die()函数的意思是将括号里的字串送到浏览器并中断PHP程式 (Script)。括号里的参数为欲送出的字串。 */
@mysql_select_db("ok", $dbh);
/* 选择mysql服务器里的一个数据库,这里选的数据库名为 ok */
$q = "SELECT * FROM abc";
/* 定义变量q, "SELECT * FROM abc"是一个SQL语句,意思是读取表abc中的数据 */
?>
$rs = mysql_query($q, $dbh);
/* 定义变量 rs ,函数mysql_query()的意思是:送出 query 字串供 MySQL 做相关的处理或者执行.由于php是从右往左执行的,所以,rs的值是服务器运行mysql_query()函数后返回的值 */
if(!$rs){die("Valid result!");}
echo "
ID | Name |
$row[0] | $row[1] |
?>
$rs = mysql_query($q, $dbh);
while($row = mysql_fetch_object($rs)) echo "$row->id $row->name
";
/* id和name可以换位置 */
?>
$rs = mysql_query($q, $dbh);
while($row = mysql_fetch_array($rs)) echo "$row[id] $row[name]
";
/* id和name可以换位置 */
?>
@mysql_close($dbh);
/* 关闭到mysql数据库的连接 */
?>

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