小白(续2)
我数据库中有表tb_manager,表中有name(al)和pwd(al),我在登录界面输入name和pwd结果还是:
您输入的管理员名称错误,请重新输入!
求大神帮忙解决
<?phpsession_start();$A_name=$_POST[name]; //接收表单提交的用户名$A_pwd=$_POST[pwd]; //接收表单提交的密码class chkinput{ //定义类 var $name; var $pwd; public function _construct($x,$y){ $this->name=$x; $this->pwd=$y; } function checkinput(){ include("conn/conn.php"); //连接数据源 $sql = mysql_query("select * from tb_manager where name='".$this->name."' and pwd='".$this->pwd."'",$conn); // echo "$sql"; $info=mysql_fetch_array($sql); //检索管理员名称和密码是否正确 if($info==false){ //如果管理员名称或密码不正确,则弹出相关提示信息 echo "<script language='javascript'>alert('您输入的管理员名称错误,请重新输入!');history.back();</script>"; exit; } else{ //如果管理员名称或密码正确,则弹出相关提示信息 echo "<script>alert('管理员登录成功!');window.location='index.php';</script>"; $_SESSION[admin_name]=$info[name]; $_SESSION[pwd]=$info[pwd]; } }} $obj=new chkinput(trim($name),trim($pwd)); //创建对象 $obj->checkinput(); //调用类?>
回复讨论(解决方案)
$A_name=$_POST[name]; //接收表单提交的用户名
$A_pwd=$_POST[pwd]; //接收表单提交的密码
$obj=new chkinput(trim($name),trim($pwd));
大神 还是不行啊
我单独测试了一下能连接db_library数据库
在$sql=。。。。。下面加一句
echo $sql;
返回的是Resource id #5
name和pwd对应的id是22
希望有助于您帮我解决问题
你的sql是连接资源
你要把参数的sql语句拿出来单独打印才行
三楼大神,我真的是小白,才接触不到半年,能不能说的再具体一点,最好能举个例子,拜托了
$A_name=$_POST[name]; //接收表单提交的用户名
$A_pwd=$_POST[pwd]; //接收表单提交的密码
$obj=new chkinput(trim( $A_name),trim( $A_pwd));
$obj=new chkinput(trim($name),trim($pwd)),这是你实例化类传入的参数。
你接收的form表单的参数是$A_name=$_POST[name] 和 $A_pwd=$_POST[pwd]。
实例化类的传入参数改一下:
$obj=new chkinput(trim($A_name),trim($A_pwd))
7楼是我,这个号是第三方百度账号上的,不过的没上一次重新点一次,我就 申请了一盒scdn的账号
大神们,这样改完就不区分大小写了

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