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Home Backend Development PHP Tutorial 来个高手啊,一个困扰我很久的php问题,求帮助

来个高手啊,一个困扰我很久的php问题,求帮助

Jun 23, 2016 pm 01:14 PM

两个php文件,一个为a.php,代码是

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<?phpfunction threadpics($tid,$num=1){   $tableid=substr($tid,-1,1); $array=array(); $rs=DB::query("SELECT aid FROM  ".DB::table("forum_attachment_{$tableid}")." WHERE  `tid` ='$tid' AND  `isimage` =1 AND `price`=0 order by aid asc LIMIT 0 , $num");    while ($rw=DB::fetch($rs)){     $array[]=$rw;   }   return $array;}?>

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另一个b.php,代码是

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<?phprequire_once './source/class/class_core.php';$discuz = & discuz_core::instance();$discuz->init();$nopic='./static/image/common/nophotosmall.gif';//ȱʡͼƬ$aid=intval($_G['gp_aid']);if(1){$tableid=DB::result_first("SELECT  `tableid` FROM  ".DB::table("forum_attachment")." WHERE  `aid` ='$aid' LIMIT 0 , 1");$attach=DB::fetch_first("SELECT * FROM  ".DB::table("forum_attachment_$tableid")." WHERE  `aid` ='{$aid}' LIMIT 0 , 1");$thumbfile="./forum/".$attach['attachment'];if(file_exists($thumbfile)){ header("location:{$thumbfile}");    die();}}?>

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网页输出图片路径是来个高手啊,一个困扰我很久的php问题,求帮助


求助把b.php文件的代码合并到a.php,网页输出用一个变量来代替,如来个高手啊,一个困扰我很久的php问题,求帮助,请帮忙给个修改后的完整代码,谢谢各位大神了


回复讨论(解决方案)

不明白你的意思!

a.php 只是定义了一个函数,b.php 中并没有调用它

不明白你的意思!

a.php 只是定义了一个函数,b.php 中并没有调用它

网页里的代码来个高手啊,一个困扰我很久的php问题,求帮助,用到了b.php,怎样把来个高手啊,一个困扰我很久的php问题,求帮助里的b.php?aid=$o[aid] 用变量来代替,比如来个高手啊,一个困扰我很久的php问题,求帮助,谢谢

贴全相关代码

贴全相关代码

你好,谢谢你的回复,htm网页的代码是这样的


来个高手啊,一个困扰我很久的php问题,求帮助


用于discuz列表页获取帖子图片的

贴全相关代码

版主啊,求帮忙

不知道你想表达什么
如果你是想让b.php 这段代码 能在a.php里运行 ,那就加在

1

while ($rw=DB::fetch($rs)){        $array[]=$rw;    }

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Copy after login
Copy after login

这段代码里,定义一个$array[‘tupian’] = (b.php 返回的值)

这样子,return $array 的时候,在html里,解析一下,就可以了

不知道你想表达什么
如果你是想让b.php 这段代码 能在a.php里运行 ,那就加在

1

while ($rw=DB::fetch($rs)){        $array[]=$rw;    }

Copy after login
Copy after login
Copy after login

这段代码里,定义一个$array[‘tupian’] = (b.php 返回的值)

这样子,return $array 的时候,在html里,解析一下,就可以了

我想表达的是能不能用变量$tupian代替b.php,然后html里解析直接是来个高手啊,一个困扰我很久的php问题,求帮助,而不是来个高手啊,一个困扰我很久的php问题,求帮助。不知道可以吗

不知道你想表达什么
如果你是想让b.php 这段代码 能在a.php里运行 ,那就加在

1

while ($rw=DB::fetch($rs)){        $array[]=$rw;    }

Copy after login
Copy after login
Copy after login

这段代码里,定义一个$array[‘tupian’] = (b.php 返回的值)

这样子,return $array 的时候,在html里,解析一下,就可以了

还有就是您说的这个代码具体怎么加,请贴一下代码,我php很初级,谢谢

dz好像有个标签,里面写$tupian = b.php?aid=$o[aid];不知道是不是你要问的
提问时最好表达简明准确,你的目的是什么,你碰到的问题是什么

dz好像有个标签,里面写$tupian = b.php?aid=$o[aid];不知道是不是你要问的
提问时最好表达简明准确,你的目的是什么,你碰到的问题是什么


谢了,大概就是你写的这个代码的意思,你的这个代码怎么加啊,
while ($rw=DB::fetch($rs)){
        $array[]=$rw;
 $tupian = b.php?aid=$o[aid];
   }
我这样加直接就报错了


dz好像有个标签,里面写$tupian = b.php?aid=$o[aid];不知道是不是你要问的
提问时最好表达简明准确,你的目的是什么,你碰到的问题是什么


谢了,大概就是你写的这个代码的意思,你的这个代码怎么加啊,
while ($rw=DB::fetch($rs)){
        $array[]=$rw;
 $tupian = b.php?aid=$o[aid];
   }
我这样加直接就报错了


我写的是语法不标准的示例,准确的是
$tupian = 'b.php?aid=' . $rw['aid'];
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