thinkphp 关于遍历菜单的问题
在thinkphp中 遍历出数据库的数据显示到模板中,
数据库
CREATE TABLE `cn_menu` ( `id` int(10) unsigned NOT NULL AUTO_INCREMENT COMMENT '系统菜单id', `pid` int(10) unsigned DEFAULT NULL COMMENT '父级id', `name` varchar(200) DEFAULT NULL COMMENT '菜单名称', `url` varchar(200) DEFAULT NULL COMMENT '菜单URL', `params` varchar(200) DEFAULT NULL COMMENT 'URL参数', `sort` tinyint(4) DEFAULT '1' COMMENT '排序', `status` tinyint(1) DEFAULT '1' COMMENT '菜单状态(1=显示,2=隐藏,0=删除)', PRIMARY KEY (`id`)) ENGINE=InnoDB AUTO_INCREMENT=13 DEFAULT CHARSET=utf8 COMMENT='系统菜单表';
这是数据库的数据
这个是菜单显示图
这个是模板 代码 但是!这个模板的数据我不要死得,要根据数据库的数据遍历出来的
<div class="sidebar"> <input type="hidden" value="{:U('SystemFunc/index')}" id="urlAjax"> <ul class="nav" id="nav" > <li class="nav-li"> <a href="###" id="aaa">系统菜单 <span class="caret"></span></a> <ul class="menu"> <li class="menu-li"><a target="main" href="{:U('SystemFunc/listMenu')}">菜单列表</a></li> <!--<li class="menu-li active"><a target="main" href="{:U('SystemFunc/listMenu')}">菜单列表</a></li>--> <li class="menu-li "><a target="main" href="{:U('SystemFunc/addMenu')}">添加菜单</a></li> </ul> </li> <li class="nav-li"> <a href="###">系统角色 <span class="caret"></span></a> <ul class="menu"> <li class="menu-li"><a target="main" href="{:U('SystemFunc/listOral')}">系统角色</a></li> <li class="menu-li"><a target="main" href="{:U('SystemFunc/addOral')}">添加角色</a></li> </ul> </li> <li class="nav-li"> <a href="###">系统管理 <span class="caret"></span></a> <ul class="menu"> <li class="menu-li"><a target="main" href="##">管理员</a></li> <li class="menu-li"><a target="main" href="{:U('SystemFunc/addAdmin')}">添加管理员</a></li> </ul> </li> </ul> </div>
1、首先遍历出数据,数据不能是死的,要根据数据库的数据循环出来
2、鼠标点击一下,就隐藏他的下级, 比如:我点击系统菜单,那么 系统菜单下面的菜单列表和添加菜单都(隐藏)收起来!再点击一次菜单列表和添加菜单 显示出来
3、试过很多方法都不管用,新入门的菜鸟求指教,万分感激!!满分奉上
回复讨论(解决方案)
根据pid从数据库取值,至于鼠标点击一下,就隐藏他的下级,这属于前端了,js,或jquery实现
根据pid从数据库取值,至于鼠标点击一下,就隐藏他的下级,这属于前端了,js,或jquery实现
可是代码怎么实现用sql遍历出数据,然后用两个for循环嵌套,第一个for循环显示pid=0的
首先在后台中将pid==0的节点找出来组成数组arr_node,然后foreach该数组,将pid==id的子数组找出来存放在之前数组中,记key为son_node,即arrnode['son_node']=array(...)。
然后在前台遍历输出,
{$vo.name}
搞个 二维数组就可以啦
php无限极分类技术,自行百度。
推荐你去慕课网看看搜搜你会有很大的收获!!!
求给分!!!
我不能给你代码,但我可以给你指条路!
先建立个获取数据并将其转换成树型结构的递归函数,这个函数可以放到公众目录的函数文件中
function getTree($data,$pid){ if (!is_array($data) || empty($data) ) return false; $tree = array(); foreach ($data as $k => $v) { if ($v['pid'] == $pid) { //当相等时,说明此数组为上个数组的子目录 $v['pid'] = getTree($data,$v['id']);//将子数组的内容遍历后赋给上级数组的pid键,html页面上循环时用到此内容 $tree[] = $v; unset($data[$k]); //删除遍历过的数组数据 } } return $tree;}
在控制器里建个方法,调用数据,并传到函数里
public function showMenu(){ $m = M('cn_menu')->field(true)->select(); $d = getTree($m,0); $this->assign('menu',$d);}
HTML页面显示内容,
<div class="sidebar"> <input type="hidden" value="{:U('SystemFunc/index')}" id="urlAjax"> <ul class="nav" id="nav" > <volist name ="menu" id="vo"> <li class="nav-li"> <a href="###" id="aaa">{$vo.name} <span class="caret"></span></a> <ul class="menu"> <volist name="vo['pid']" name="vi"> <li class="menu-li"><a target="main" href="{:U('SystemFunc/listMenu')}">{$vi.name}</a></li> </volist> </ul> </li> </volist> </ul> </div>
整体原理就是,通过递归函数循环遍历多维数组,生成有对应关系的树型数组,代码全手写,有部分参考别人的,刚好我也在用这块的内容,给你看看

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