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Home Backend Development PHP Tutorial PHP的url参数获取问题,如何快速获取所需参数

PHP的url参数获取问题,如何快速获取所需参数

Jun 23, 2016 pm 01:26 PM

http://www.abc.com/content/5176.asp?page=1&5176__2#p

当前url是这个链接
我现在需要在当前页面上生成1个链接
http://www.abc.com/content/5176.asp?page=1&author=10000

如何快速完成??
我的做法是:

function ghref($param){	$url = "http://".$_SERVER['HTTP_HOST'].$_SERVER['REQUEST_URI']; //获取url	$query_str = parse_url($url, PHP_URL_QUERY); //获取url问号后的值,不包括#	$query_str =explode("&",$query_str); //切割成数组	$arr=array();     foreach($query_str  as $v){           	if(preg_match("/=/",$v)){        		$arr[] = $v;  //标准的键名=参数值,就留下        	}     }     $str = implode("&",$arr); //变成url字符串	parse_str($str,$myArray); //再次分成数组形式	$myArray['page']=$param; //修改其中某个键名的值       $myArray['author']=1000;	return substr($url,0,strpos($url,"?"))."?".http_build_query($myArray); //完整拼接}
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我觉得有点繁琐了,哪路大神有简便的做法???


回复讨论(解决方案)

你的 asp 也用 php 解析?
对于 http://www.abc.com/content/5176.asp?page=1&5176__2#p
$_GET 是这样的数组 array('page' => 1, '5176__2' => ''),#p 不会被 php 利用
于是你可以 $_GET = array_diff($_GET, array('')); 得到这样的数组 array('page' => 1)
$_GET['author'] = 1000;
return ""http://$_SERVER[HTTP_HOST]/$_SERVER[PHP_SELF]?" . http_build_query($_GET);

膜拜xuzuning大神,非常感谢帮助

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